y=2/3x^2-3

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Solution for y=2/3x^2-3 equation: 


x in (-oo:+oo)

y = (2/3)*x^2-3 // - (2/3)*x^2-3

y-((2/3)*x^2)+3 = 0

(-2/3)*x^2+y+3 = 0

-2/3*x^2 = -(y+3) // : -2/3

x^2 = 3/2*(y+3)

x^2 = 3/2*(y+3) // ^ 1/2

abs(x) = (3/2)^(1/2)*(y+3)^(1/2)

x = (3/2)^(1/2)*(y+3)^(1/2) or x = -((3/2)^(1/2)*(y+3)^(1/2))

x in { (3/2)^(1/2)*(y+3)^(1/2), -((3/2)^(1/2)*(y+3)^(1/2)) }

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